In the following reaction $X$ is
$CH_3NH_2 + X + KOH \to CH_3NC$ (highly offensive odour)

Arrange the following compounds in decreasing order of basic strength:
$(i)$ Aniline
(ii) $p$-Nitroaniline
(iii) $p$-Cyanoaniline
(iv) $p$-Toluidine

In the reaction sequence: $C_6H_5NH_2$ $\xrightarrow{CHCl_3/KOH, \Delta} (X)$ $\xrightarrow{LiAlH_4/H_2O} (Y)$,the product $(Y)$ is:

Which of the following is the correct order for basic strength?

$A$ compound of molecular weight $180$ is acetylated to give a compound of molecular weight $390$. The number of amino groups in the initial compound is:

Reduction of nitrobenzene with $Zn$ and alcoholic $KOH$ solution results in the formation of the following compound: